#列表+循环 实现，并包装成一个函数def pySum(n):    a = list(range(10))    b = list(range(0,5*n,5))    c = []    for i in range(len(b)):        c.append(a[i]+b[i])    return (c)print(pySum(10))

运行结果：

import numpydef arySum(n):    a = numpy.arange(n)    b = numpy.arange(0,2*n,2)    c = a+b    return (c)print(arySum(10))

运行结果：

 

 

#列表实现数组相加的效率from datetime import datetimes_sum = datetime.now()pySum(1000000)delta_sum = datetime.now()-s_sumprint(delta_sum)#实现数组相加的效率numpys_numpy = datetime.now()arySum(1000000)delta_numpy = datetime.now()-s_numpyprint(delta_numpy)

运行结果：